Introduction to Electrochemistry
Electrochemistry is the study of interchange of chemical and electrical energy.
Oxidation/Reduction involves the exchange of electrons from one chemical species to another. Normally, this is done when the two chemicals contact each other in the activated complex (when two species bump into each other in solution for example).
We are interested in separating the chemical species such that the electrons transfer via an external circuit. That way, we can measure the electrochemical effects.
To properly understand the connection between the redox reaction and the electricity, we should balance the overall redox reaction using a half-reaction method such as the one described in the previous section of these notes. We can set up the physical reaction vessel such that the chemicals from one half reaction are separated from those of the second half reaction. For reaction to occur, we still need to connect the solutions to complete the circuit. This is done by attaching wires between electrodes in the two half cells and by connecting the solutions of the two half cells via a salt bridge or by some other device such as a semi-permeable membrane.
In general, such a cell is called an electrochemical cell. These cells could be used in one of two types of situations:
- The chemical reaction is spontaneous and produces electricity.
This is called a voltaic cell or a galvanic cell. - The chemical reaction is non-spontaneous and is forced by electricity from an external source.
This kind of cell is called an electrolysis cell.
We will look at the first situation first.
Galvanic or Voltaic cells
Consider a piece of zinc foil placed in a beaker of copper sulphate. The copper sulphate solution is blue because of the presence of the Cu2+ ions. When the zinc is added, the solution changes to colourless and the zinc metal is dissolved and replaced by a reddish orange powder. The colourless solution no longer has Cu2+ in it and the reddish orange powder is Cu(s). The Zn(s) is dissolved and is now Zn2+. [I know this because of my vast knowledge of chemistry ;-)]
If we write an overall reaction for this process, we get:
Zn + Cu2+
Zn2+ + Cu. This doesn't help us in our quest for electrochemistry knowledge. Let's rewrite this in half-reaction form.
Zn
Zn2+ + 2e-
Cu2+ + 2e-
Cu
Now, we can set up two half cells, one with a zinc electrode in a Zn2+ solution (say ZnSO4) and the other with a copper electrode in a Cu2+ solution (say CuSO4) as follows.
The centre line in the diagram, recall, is either a semi-permeable membrane or a salt bridge.
Now, at the anode, we have the reaction
Zn(s)Zn2+(aq) + 2e-(aq)
and at the cathode, we have
Cu2+(aq) + 2e-(aq)Cu(s)
Electrons pass through the wires and SO42- pass through the membrane to keep the solutions neutral.
Cell Potentials
Electrons from solution pushed onto the anode, around the external circuit and onto the cathode where they are pulled out into the solution.
That's one way of thinking of the electrical circuit part of the electrochemical cell. The electrons pushed around the external circuit can do work (run a motor, illuminate a light bulb, etc). The amount of work possible is a function of both the voltage (potential) and of the current (number of electrons) in the circuit.
Pushing one Coulomb of charge around a circuit at a potential of 1 Volt does One Joule of work. OR, mathematically, 1J = 1V × 1C.
The cell potential (voltage of the cell) depends on the chemicals used. For example, the chemicals in dry-cells(batteries) are such that the potential is always about 1.5 V. This has become a standard and is now a limiting factor in deciding which chemicals can be used to create a battery.
The cell potential is given a symbol of Ecell. If all chemicals are at activity of 1 (conc. = 1 M, p = 1 bar) then the cell potential is the standard cell potential and is given as E°cell.
Any redox reaction has the potential (pun) to be used in an electrochemical cell. We merely need to be able to divide the oxidizing and reducing agents into two half cells (half reactions).
Take for example, the reaction of zinc metal dissolving in hydrochloric acid. The reaction is:
Zn(s) + 2H+(aq)Zn2+(aq) + H2(g)
We need to separate the zinc from the hydrogen. We can use zinc as an electrode but what about the hydrogen.
In this case, we need to set up a special electrode, which allows H2 gas molecules to interact directly with H+dissolved in water and with the electrons from the external circuit simultaneously. Such a system is pictured below.
A blow-up of the surface of the platinum electrode is shown below so the location of reaction can be better understood.
The other half-cell would look much like that pictured in a previous diagram. The whole cell diagram, of course would include the external part of the circuit and the salt bridge or membrane to complete the circuit. We can abbreviate this diagram as follows:
Zn(s)/ZnSO4(aq)//H2SO4(aq)/H2(g),Pt(s)
[Anode // Cathode]
Where the single slash mark / represents the boundary between solution and electrode and the double slash //represents the salt bridge or semi-permeable membrane. The external circuit, of course, joins the two electrodes (solid) and is not explicitly shown here.
The overall cell voltage can be summed from the half-cell potentials of the oxidation and of the reduction reactions.
Ecell = ERed + Eox.
Standard Reduction Potentials
As before, we wish to tabulate thermodynamic data in some useable way. We define a standard set of conditions under which all half-reactions can theoretically operate and we tabulate the half-cell potentials for the reactions under standard conditions. Since the potential of an oxidation reaction (loose electron) is merely the negative of the potential for a reduction reaction reaction (gain electron), we choose to tabulate only the reduction half-reactions. Any oxidation half reactions are merely the reverse of the tabulated reduction reaction and the oxidation potential is the negative of the tabulate reduction potential.
Table D.4 from Petrucci lists many reduction half-reactions that you will need for problems, etc in the text. Herein, I have duplicated only a few in the following table.
| reduction | Eº/volts | |
|---|---|---|
| 1 | O2 + 4H+ + 4e- | +1.229 |
| 2 | Ag+ + e- | +0.7996 |
| 3 | Cu2+ + 2 e- | +0.3419 |
| 4 | Fe2+ + 2 e- | -0.447 |
| 5 | Zn2+ + 2 e- | -0.7628 |
| 6 | 2H2O + 2e- | -0.83 |
| 7 | Na+ + e- | -2.71 |
| A few years ago, a city experienced a number of very serious water main breaks on sections of pipe that had been recently replaced. The City engineer was fired. His onlydefence was "How was I to know that brass fittings (mostly copper) on cast iron pipes would corrode so fast." Was the city justified in firing him? Can you explain their reasoning for calling him incompetent? |
Let's look at this small reduction potential table and see if we can use it to explain certain experimentally observable properties of matter. First off, I should point out that the more positive reduction potentials refer to more spontaneous reduction reactions.
The first reaction in this mini-table shows the reduction of oxygen. This is higher in the table than many other things. That makes sense since we know that oxygen is a good oxidizing agent (it makes other things oxidize while it itself is reduced).
We can see that water can be both oxidized (-1) and reduced (2). It is oxidized to oxygen and reduced to hydrogen. These two reactions, in fact, serve as a set of boundaries for aqueous solutions. Any materials harder to oxidize than water will not oxidize since the water will. Similarly, any materials harder to reduce than water will never reduce (in water). For example, sodium ions will never reduce to sodium metal in the presence of water since the water will reduce first. In fact, sodium metal in water will spontaneously (explosively) oxidize to Na+ ions and the water will reduce to hydrogen gas and leave a basic solution (equation 6). The overall reaction for this process is the sum (#6) - 2×(#7).
| NOTE: when we add half-cells, their potentials are strictly additive. We don't multiply or divide by any factors even though we do so to the stoichiometric coefficients of the equations in order to balance the overall equation. Potentials don't depend on the total amount or size of the cell, just the concentrations. You already know this. If you buy a AA cell or a D cell, their voltages are both 1.5V. However, their capacity to do work is not the same. |
2Na + 2 H2O
2Na+ + H2 + 2OH-
Thus, the overall standard cell potential for this reaction is
Eºcell = Eºred + Eºox = -0.83 + 2.71 (reverse reaction => change sign) = 1.88 V.
Positive cell potential means spontaneous reaction.
When pairing up metals, we know that zinc will dissolve in a copper (II) solution. Here we see that the copper (II) (3) is easier to reduce than the zinc (II) (5)

